9/64=p^2

Solution for 9/64=p^2 equation:

9/64=p^2

We move all terms to the left:

9/64-(p^2)=0

We add all the numbers together, and all the variables

-1p^2+9/64=0

We multiply all the terms by the denominator


-1p^2*64+9=0

Wy multiply elements

-64p^2+9=0

a = -64; b = 0; c = +9;
Δ = b2-4ac
Δ = 02-4·(-64)·9
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48}{2*-64}=\frac{-48}{-128}
=3/8
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48}{2*-64}=\frac{48}{-128}
=-3/8
$